streaming.pass.cpp (2235B)
1 //===----------------------------------------------------------------------===// 2 // 3 // The LLVM Compiler Infrastructure 4 // 5 // This file is dual licensed under the MIT and the University of Illinois Open 6 // Source Licenses. See LICENSE.TXT for details. 7 // 8 //===----------------------------------------------------------------------===// 9 // UNSUPPORTED: c++98, c++03, c++11, c++14, c++17 10 // XFAIL: * 11 12 // <chrono> 13 // class year_month_day; 14 15 // template<class charT, class traits> 16 // basic_ostream<charT, traits>& 17 // operator<<(basic_ostream<charT, traits>& os, const year_month_day& ym); 18 // 19 // Returns: os << ym.year() << '/' << ym.month(). 20 // 21 // 22 // template<class charT, class traits> 23 // basic_ostream<charT, traits>& 24 // to_stream(basic_ostream<charT, traits>& os, const charT* fmt, const year_month_day& ym); 25 // 26 // Effects: Streams ym into os using the format specified by the NTCTS fmt. fmt encoding follows the rules specified in 25.11. 27 // 28 // template<class charT, class traits, class Alloc = allocator<charT>> 29 // basic_istream<charT, traits>& 30 // from_stream(basic_istream<charT, traits>& is, const charT* fmt, 31 // year_month_day& ym, basic_string<charT, traits, Alloc>* abbrev = nullptr, 32 // minutes* offset = nullptr); 33 // 34 // Effects: Attempts to parse the input stream is into the year_month_day ym using the format 35 // flags given in the NTCTS fmt as specified in 25.12. If the parse fails to decode 36 // a valid year_month_day, is.setstate(ios_- base::failbit) shall be called and ym shall 37 // not be modified. If %Z is used and successfully parsed, that value will be assigned 38 // to *abbrev if abbrev is non-null. If %z (or a modified variant) is used and 39 // successfully parsed, that value will be assigned to *offset if offset is non-null. 40 41 42 43 #include <chrono> 44 #include <type_traits> 45 #include <cassert> 46 #include <iostream> 47 48 #include "test_macros.h" 49 50 int main() 51 { 52 using year_month_day = std::chrono::year_month_day; 53 using year = std::chrono::year; 54 using month = std::chrono::month; 55 using day = std::chrono::day; 56 57 std::cout << year_month_day{year{2018}, month{3}, day{12}}; 58 }